What is the domain of sqrt((x-4)(2x+5)^2(x-7)) ?

The domain of sqrt((x-4)(2x+5)^2(x-7)) is x = 7

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domain of sqrt((x-4)(2x+5)^2(x-7))

domain

(x - 4) (2 x + 5)^{2} (x - 7)

x \leq 4 or x \geq 7

Interval Notation

(- \infty, 4] \cup [7, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 4 or x \geq 7

The function domain

x \leq 4 or x \geq 7

f (x) = \frac{6}{x - 5}

- 3 tan (3 x + π) + 2

lo g_{10} (x + 2) - 3

lo g_{10} (x + 2) - 4

\frac{5 x}{( x - 10 ) x ^{2} - x - 30}

What is the domain of sqrt((x-4)(2x+5)^2(x-7)) ?
The domain of sqrt((x-4)(2x+5)^2(x-7)) is x<= 4\lor x>= 7