What is the domain of f(x)= t/(sqrt(9-t^2)) ?

The domain of f(x)= t/(sqrt(9-t^2)) is -3<t<3

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domain of f(x)= t/(sqrt(9-t^2))

domain

f (x) = \frac{t}{9 - t ^{2}}

- 3 < t < 3

Interval Notation

(- 3, 3)

Solution steps

Find non-negative values for radicals:

- 3 \leq t \leq 3

Find undefined (singularity) points:

t = 3, t = - 3

Combine real regions and undefined points for final function domain

- 3 < t < 3

f (x) = x - x + 8

x^{3} + 2 x

6.75 4 + 12

f (x) = ln (- x^{2} + 5 x - 6)

\frac{- 3 x + 1}{4 x + 3}

What is the domain of f(x)= t/(sqrt(9-t^2)) ?
The domain of f(x)= t/(sqrt(9-t^2)) is -3<t<3