What is the domain of f(x)=-sqrt(1+3x)+5 ?

The domain of f(x)=-sqrt(1+3x)+5 is x>=-1/3

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domain of f(x)=-sqrt(1+3x)+5

domain

f (x) = - 1 + 3 x + 5

x \geq - \frac{1}{3}

Interval Notation

[- \frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{3}

The function domain

x \geq - \frac{1}{3}

f (x) = \frac{5}{x ^{2} - 5 x + 6}

f (x) = \frac{1}{lo g _{10} ( x ^{2} + 10 x + 25 )}

f (x) = \frac{( x + 3 )}{( x - 4 )}

f (x) = - - x + 3

What is the domain of f(x)=-sqrt(1+3x)+5 ?
The domain of f(x)=-sqrt(1+3x)+5 is x>=-1/3