What is the domain of f(x)=(x^2+x+1)/(x-3) ?

The domain of f(x)=(x^2+x+1)/(x-3) is x 3

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domain of f(x)=(x^2+x+1)/(x-3)

domain

f (x) = \frac{x ^{2} + x + 1}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

\frac{x - 4}{2 x + 1}

p (x) = x

2 cos (- 2 x)

f (x) = ln (\frac{2 x - 2}{9 - x ^{2}})

What is the domain of f(x)=(x^2+x+1)/(x-3) ?
The domain of f(x)=(x^2+x+1)/(x-3) is x<3\lor x>3