What is the domain of y= x/(1-x^2)+sqrt(x+1) ?

The domain of y= x/(1-x^2)+sqrt(x+1) is -1 1

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domain of y= x/(1-x^2)+sqrt(x+1)

domain

y = \frac{x}{1 - x ^{2}} + x + 1

- 1 < x < 1 or x > 1

Interval Notation

(- 1, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

- 1 < x < 1 or x > 1

\frac{x ^{2} - 9}{x ^{2} - 2}

f (x) = \frac{x - 1}{x + 1} - 1

f (x) = 2 + n cos (x)

\frac{2 x + 3}{2 x ^{2} + x - 1}

f (x) = (\frac{7 x}{x - 5})

What is the domain of y= x/(1-x^2)+sqrt(x+1) ?
The domain of y= x/(1-x^2)+sqrt(x+1) is -1<x<1\lor x>1