What is the domain of f(x)=(x^2-4)/(2+sqrt(x-1)) ?

The domain of f(x)=(x^2-4)/(2+sqrt(x-1)) is x>= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x^2-4)/(2+sqrt(x-1))

domain

f (x) = \frac{x ^{2} - 4}{2 + x - 1}

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = \frac{x ^{2} + 2 x - 3}{x ^{2} + 5 x + 6}

f (x) = \frac{3}{x - 3}

7 x^{2} + 8

f (x) = x^{(3)} - 7 x^{(2)} + 10 x

f (x) = 2 \cdot 2^{x}

What is the domain of f(x)=(x^2-4)/(2+sqrt(x-1)) ?
The domain of f(x)=(x^2-4)/(2+sqrt(x-1)) is x>= 1