What is the domain of h(x)=(x^2-9)/(x-2) ?

The domain of h(x)=(x^2-9)/(x-2) is x 2

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domain of h(x)=(x^2-9)/(x-2)

domain

h (x) = \frac{x ^{2} - 9}{x - 2}

x < 2 or x > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2

The function domain

x < 2 or x > 2

y = e^{3} (e - 2 a)

- 3 x + 2 - 6

f (x) = \frac{3 - 7 x}{8 x}

f (x) = 3 (x - 2)^{2} - 9

f (x) = e^{0 + 2}

What is the domain of h(x)=(x^2-9)/(x-2) ?
The domain of h(x)=(x^2-9)/(x-2) is x<2\lor x>2