What is the domain of f(x)=sqrt(x-4)+1 ?

The domain of f(x)=sqrt(x-4)+1 is x>= 4

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domain of f(x)=sqrt(x-4)+1

domain

f (x) = x - 4 + 1

x \geq 4

Interval Notation

[4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

The function domain

x \geq 4

f (x) = \frac{5}{e ^{x} - 1}

x^{4} - 2 x^{2} - 3

x^{4} - 2 x^{2} - 1

(x - 2) (x + 3)

f (x) = \frac{1}{( x + 7 ) ( x + 8 )}

What is the domain of f(x)=sqrt(x-4)+1 ?
The domain of f(x)=sqrt(x-4)+1 is x>= 4