What is the domain of y=sqrt(1-2x)-sqrt(3-2x-x^2) ?

The domain of y=sqrt(1-2x)-sqrt(3-2x-x^2) is -3<= x<= 1/2

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domain of y=sqrt(1-2x)-sqrt(3-2x-x^2)

domain

y = 1 - 2 x - 3 - 2 x - x^{2}

- 3 \leq x \leq \frac{1}{2}

Interval Notation

[- 3, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq \frac{1}{2}

The function domain

- 3 \leq x \leq \frac{1}{2}

f (x) = 4 - \frac{4}{3} x

f (x) = \frac{x + 2}{7 x ^{2} + 28 x}

f (x) = \frac{6 x}{2 x - 4}

f (x) = \frac{10}{t ^{2} - 100}

ln (- 2 x)

What is the domain of y=sqrt(1-2x)-sqrt(3-2x-x^2) ?
The domain of y=sqrt(1-2x)-sqrt(3-2x-x^2) is -3<= x<= 1/2