What is the domain of (x^2+4)/(4x^2-4x-8) ?

The domain of (x^2+4)/(4x^2-4x-8) is x 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (x^2+4)/(4x^2-4x-8)

domain

\frac{x ^{2} + 4}{4 x ^{2} - 4 x - 8}

x < - 1 or - 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 1

The function domain

x < - 1 or - 1 < x < 2 or x > 2

\frac{( x ^{2} ∣ x ∣ )}{ln ( x ^{2} + 1 )}

(x^{2} + x) (x^{2} - 7)

f (x) = \frac{9}{9 x + 8}

f (x) = ∣ x - 1 ∣ - ∣ 2 x + 1 ∣

f (x) = \frac{( 2 x + 1 )}{( 2 x - 6 )}

What is the domain of (x^2+4)/(4x^2-4x-8) ?
The domain of (x^2+4)/(4x^2-4x-8) is x<-1\lor-1<x<2\lor x>2