What is the domain of f(x)= 1/(\sqrt[3]{x-4)} ?

The domain of f(x)= 1/(\sqrt[3]{x-4)} is x 4

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domain of f(x)= 1/(\sqrt[3]{x-4)}

domain

x < 4 or x > 4

Interval Notation

(- \infty, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4

The function domain

x < 4 or x > 4

\frac{19}{6 ( x - 5 )}

f (x) = \frac{x - 1}{x ^{2} + 10 x - 11}

y = \frac{x + 7}{x ^{3} + 3 x ^{2} + 3 x + 1}

f (x) = \frac{x + 6}{7 x + 6}

f (x) = 5 x^{2} - 5 x - 2

What is the domain of f(x)= 1/(\sqrt[3]{x-4)} ?
The domain of f(x)= 1/(\sqrt[3]{x-4)} is x<4\lor x>4