What is the domain of h(x)=sqrt(x+15) ?

The domain of h(x)=sqrt(x+15) is x>=-15

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domain of h(x)=sqrt(x+15)

domain

h (x) = x + 15

x \geq - 15

Interval Notation

[- 15, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 15

The function domain

x \geq - 15

\frac{7}{x ^{2} - 16} - \frac{( x + 4 )}{x ^{2} - 8 x + 16}

f (x) = \frac{5 x - 6}{5 x + 40}

x^{3} - 64

f (x) = \frac{x + 3}{8}

f (x) = \frac{x ( x - 1 )}{x + 5}