What is the domain of f(x)=-sqrt(4x+5)+1/(5x^2+2) ?

The domain of f(x)=-sqrt(4x+5)+1/(5x^2+2) is x>=-5/4

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domain of f(x)=-sqrt(4x+5)+1/(5x^2+2)

domain

f (x) = - 4 x + 5 + \frac{1}{5 x ^{2} + 2}

x \geq - \frac{5}{4}

Interval Notation

[- \frac{5}{4}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{5}{4}

The function domain

x \geq - \frac{5}{4}

\frac{4}{( x - 7 ) ^{2}}

9 \cdot \frac{2}{3} + 5

f (t) = ln (2 t + 5)

f (x) = \frac{1}{2} sin (\frac{1}{2}) (x + \frac{π}{4})

\frac{2 ln ( x ^{3} + 1 )}{3} + \frac{1}{2}

What is the domain of f(x)=-sqrt(4x+5)+1/(5x^2+2) ?
The domain of f(x)=-sqrt(4x+5)+1/(5x^2+2) is x>=-5/4