What is the domain of 1/2 sqrt(-9x^2-36x)+3 ?

The domain of 1/2 sqrt(-9x^2-36x)+3 is -4<= x<= 0

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domain of 1/2 sqrt(-9x^2-36x)+3

domain

\frac{1}{2} - 9 x^{2} - 36 x + 3

- 4 \leq x \leq 0

Interval Notation

[- 4, 0]

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq 0

The function domain

- 4 \leq x \leq 0

f (x) = x \cdot lo g_{10} (π)

f (x) = \frac{π}{6} - 2 arcsin (1 - 2 x)

\frac{( x + 9 )}{( x ^{2} - 16 )}

f (x) = \frac{8 x ^{2} - 10 x}{x ^{2} + 2 x - 8}

f (x) = (- 3 x + 5) + x + 4

What is the domain of 1/2 sqrt(-9x^2-36x)+3 ?
The domain of 1/2 sqrt(-9x^2-36x)+3 is -4<= x<= 0