What is the domain of f(x)=5*sqrt(1-x)-3,x>-8 ?

The domain of f(x)=5*sqrt(1-x)-3,x>-8 is -8<x<= 1

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domain of f(x)=5*sqrt(1-x)-3,x>-8

domain

f (x) = 5 \cdot 1 - x - 3, x > - 8

- 8 < x \leq 1

Interval Notation

(- 8, 1]

Solution steps

Set the domain to the given interval

x > - 8

Find non-negative values for radicals:

x \leq 1

Join real regions with the domain:

x \leq 1 and x > - 8

- 8 < x \leq 1

(x - 8)^{2} + 5

\frac{x ^{2}}{x ^{2} - x - 2}

h (x) = - 8 x + 40

f (x) = 49 - x

\frac{x ^{3}}{x ^{2} + x - 2}

What is the domain of f(x)=5*sqrt(1-x)-3,x>-8 ?
The domain of f(x)=5*sqrt(1-x)-3,x>-8 is -8<x<= 1