What is the domain of sqrt(y)=1-sqrt(x) ?

The domain of sqrt(y)=1-sqrt(x) is x>= 0

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domain of sqrt(y)=1-sqrt(x)

domain

y = 1 - x

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = \frac{( x + 1 ) ^{3}}{( x - 3 ) ^{2}}

f (x) = - 2 \cdot (0.5)^{x}

\frac{x + 1}{x + \frac{2}{3}}

f (x) = \frac{x}{1 - 9 x}

2 sin (\frac{π}{2} x + 3)

What is the domain of sqrt(y)=1-sqrt(x) ?
The domain of sqrt(y)=1-sqrt(x) is x>= 0