What is the domain of f(x)=sqrt(x-2)(3x^2-7x+5)/(sqrt(9-x^2)) ?

The domain of f(x)=sqrt(x-2)(3x^2-7x+5)/(sqrt(9-x^2)) is 2<= x<3

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domain of f(x)=sqrt(x-2)(3x^2-7x+5)/(sqrt(9-x^2))

domain

f (x) = x - 2 \frac{3 x ^{2} - 7 x + 5}{9 - x ^{2}}

2 \leq x < 3

Interval Notation

[2, 3)

Solution steps

Find non-negative values for radicals:

2 \leq x \leq 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

2 \leq x < 3

(\frac{x ^{2} + 2 x}{x ^{2} + 7})^{5 x}

- 4^{x}

\frac{( x - 20 )}{- 0.025}

y = 3 x + 4

f (x) = \frac{sin ( x )}{x - 4}

What is the domain of f(x)=sqrt(x-2)(3x^2-7x+5)/(sqrt(9-x^2)) ?
The domain of f(x)=sqrt(x-2)(3x^2-7x+5)/(sqrt(9-x^2)) is 2<= x<3