What is the domain of f(x)=log_{3}(1/(x-2)) ?

The domain of f(x)=log_{3}(1/(x-2)) is x>2

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domain of f(x)=log_{3}(1/(x-2))

domain

f (x) = lo g_{3} (\frac{1}{x - 2})

x > 2

Interval Notation

(2, \infty)

Solution steps

Find positive values for logs:

x > 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

f (x) = f (x) = \frac{2}{x}

cos (arctan (x))

\frac{4 - x ^{2}}{x ^{2} + x}

f (x) = 2 \cdot e^{x^{2} - 4 x}

x^{2} + 14 x + 7

What is the domain of f(x)=log_{3}(1/(x-2)) ?
The domain of f(x)=log_{3}(1/(x-2)) is x>2