What is the domain of f(x)=-sqrt(x^2+1) ?

The domain of f(x)=-sqrt(x^2+1) is -infinity <x<infinity

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domain of f(x)=-sqrt(x^2+1)

domain

f (x) = - x^{2} + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{3 x}{5 + 4 x}

2 + (x - 1)^{\frac{1}{3}}

\frac{4 x + 1}{2 x}

- \frac{1}{3}

f (x) = lo g_{10} (2) (x + 9)

What is the domain of f(x)=-sqrt(x^2+1) ?
The domain of f(x)=-sqrt(x^2+1) is -infinity <x<infinity