What is the critical f(x)=3+4x^2-1/2 x^4 ?

The critical f(x)=3+4x^2-1/2 x^4 is x=-2,x=0,x=2

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critical f(x)=3+4x^2-1/2 x^4

critical points

f (x) = 3 + 4 x^{2} - \frac{1}{2} x^{4}

x = - 2, x = 0, x = 2

Solution steps

3 + 4 x^{2} - \frac{1}{2} x^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

3 + 4 x^{2} - \frac{1}{2} x^{4} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 2

4 x + 5 y = - 30

f (x) = \frac{5}{x + 8}

f (x) = \frac{1}{4 π}

\frac{- 2 x + 6}{x ^{2} - 9}

(- 2.1) (- 20.9)

What is the critical f(x)=3+4x^2-1/2 x^4 ?
The critical f(x)=3+4x^2-1/2 x^4 is x=-2,x=0,x=2