What is the domain of f(x)=sqrt(x+9)+8 ?

The domain of f(x)=sqrt(x+9)+8 is x>=-9

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domain of f(x)=sqrt(x+9)+8

domain

f (x) = x + 9 + 8

x \geq - 9

Interval Notation

[- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

The function domain

x \geq - 9

\frac{5 - 5 y}{2}

f (x) = ln (6 x - 9)

f (x) = - \frac{1}{2} (y - 5)^{2} + 9

f (x) = arccos (- 2 x^{2} + 3)

f (x) = (3 x + 4) (2 x^{2} + 3 x)

What is the domain of f(x)=sqrt(x+9)+8 ?
The domain of f(x)=sqrt(x+9)+8 is x>=-9