What is the domain of f(x)=((2x^2-x-3))/((2x^2+2x)) ?

The domain of f(x)=((2x^2-x-3))/((2x^2+2x)) is x 0

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domain of f(x)=((2x^2-x-3))/((2x^2+2x))

domain

f (x) = \frac{( 2 x ^{2} - x - 3 )}{( 2 x ^{2} + 2 x )}

x < - 1 or - 1 < x < 0 or x > 0

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 1

The function domain

x < - 1 or - 1 < x < 0 or x > 0

f (x) = \frac{2}{x + 9}

f (x) = 3 x^{2} - 25 x + 42

- \frac{5}{2 3 + 5 x}

f (x) = 15 + 2 x

y = \frac{2 x ^{2} - 3}{x ^{2} + 1}

What is the domain of f(x)=((2x^2-x-3))/((2x^2+2x)) ?
The domain of f(x)=((2x^2-x-3))/((2x^2+2x)) is x<-1\lor-1<x<0\lor x>0