What is the domain of 3x^2*sqrt(x+7) ?

The domain of 3x^2*sqrt(x+7) is x>=-7

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domain of 3x^2*sqrt(x+7)

domain

3 x^{2} \cdot x + 7

x \geq - 7

Interval Notation

[- 7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 7

The function domain

x \geq - 7

f (x) = \frac{x}{x ^{2} - 2 x}

f (x) = ln (2 - e^{x}) - 2 x

f (x) = - (x - 3)^{2} + 3

y = \frac{( x + 2 )}{( x - 2 )}

\frac{5 x + 2}{x ^{2} - 4}