What is the domain of f(x)=((x-3))/(x^2+6x+9) ?

The domain of f(x)=((x-3))/(x^2+6x+9) is x -3

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domain of f(x)=((x-3))/(x^2+6x+9)

domain

f (x) = \frac{( x - 3 )}{x ^{2} + 6 x + 9}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3

The function domain

x < - 3 or x > - 3

cosh (t)

\frac{x - 4}{4 x}

y = 20 x

f (x) = \frac{1}{t} t + 1

What is the domain of f(x)=((x-3))/(x^2+6x+9) ?
The domain of f(x)=((x-3))/(x^2+6x+9) is x<-3\lor x>-3