What is the domain of f(x)=sqrt((x^2-4)(x+6)) ?

The domain of f(x)=sqrt((x^2-4)(x+6)) is -6 = 2

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domain of f(x)=sqrt((x^2-4)(x+6))

domain

f (x) = (x^{2} - 4) (x + 6)

- 6 \leq x \leq - 2 or x \geq 2

Interval Notation

[- 6, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq - 2 or x \geq 2

The function domain

- 6 \leq x \leq - 2 or x \geq 2

x (160 - x)

9 - (x - 1)^{2}

f (x) = \frac{2 - x}{x + 7}

- 2 lo g_{10} (- 2 x) - 2

f (x) = \frac{x - 7}{x ^{2} - 4}

What is the domain of f(x)=sqrt((x^2-4)(x+6)) ?
The domain of f(x)=sqrt((x^2-4)(x+6)) is -6<= x<=-2\lor x>= 2