What is the domain of f(x)=(1/((x+1)))/(x^2-4) ?

The domain of f(x)=(1/((x+1)))/(x^2-4) is x 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(1/((x+1)))/(x^2-4)

domain

f (x) = \frac{\frac{1}{( x + 1 )}}{x ^{2} - 4}

x < - 2 or - 2 < x < - 1 or - 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2, x = - 1

The function domain

x < - 2 or - 2 < x < - 1 or - 1 < x < 2 or x > 2

f (x) = x^{3} - 2 x^{2}

x + 2 - 8

f (x) = \frac{( t + 2 )}{15 - t}

x - 3 - x^{2} + 4

f (x) = \frac{1}{48 x ^{4} - 72 x ^{2} + 29}

What is the domain of f(x)=(1/((x+1)))/(x^2-4) ?
The domain of f(x)=(1/((x+1)))/(x^2-4) is x<-2\lor-2<x<-1\lor-1<x<2\lor x>2