What is the domain of f(x)=(sqrt(9-x^2))^2-9 ?

The domain of f(x)=(sqrt(9-x^2))^2-9 is -3<= x<= 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sqrt(9-x^2))^2-9

domain

f (x) = (9 - x^{2})^{2} - 9

- 3 \leq x \leq 3

Interval Notation

[- 3, 3]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

The function domain

- 3 \leq x \leq 3

2 arcsin (3 x + 1) - \frac{π}{2}

y = \frac{x - 4}{x ^{2}}

8 x^{4} - 14 x^{3} - 9 x^{2} + 11 x - 1

6 x^{3} - 5 x^{2} - 6 x

lo g_{10} (x^{2} - 9)

What is the domain of f(x)=(sqrt(9-x^2))^2-9 ?
The domain of f(x)=(sqrt(9-x^2))^2-9 is -3<= x<= 3