What is the domain of f(x)=((x^2+13x+36))/(x^2-1) ?

The domain of f(x)=((x^2+13x+36))/(x^2-1) is x 1

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domain of f(x)=((x^2+13x+36))/(x^2-1)

domain

f (x) = \frac{( x ^{2} + 13 x + 36 )}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = ln (x) - ln (x + 2)

f (x) = 2 cos (t) + sin (2 t)

2 x - 2 sin (x)

2 - x^{2} - x

f (x) = 2 x - 1, x > 0

What is the domain of f(x)=((x^2+13x+36))/(x^2-1) ?
The domain of f(x)=((x^2+13x+36))/(x^2-1) is x<-1\lor-1<x<1\lor x>1