What is the domain of y=(arccos((2x)/(1+x))) ?

The domain of y=(arccos((2x)/(1+x))) is -1/3 <= x<= 1

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domain of y=(arccos((2x)/(1+x)))

domain

y = (arccos (\frac{2 x}{1 + x}))

- \frac{1}{3} \leq x \leq 1

Interval Notation

[- \frac{1}{3}, 1]

Solution steps

Find known functions domain restrictions:

- \frac{1}{3} \leq x \leq 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

- \frac{1}{3} \leq x \leq 1

f (x) = e^{2} x - 3 e x + 2

f (x) = \frac{2}{( 1 - 2 x )}

\frac{x ^{2} - 2 x}{6 x} - \frac{3 x ^{2} - 15 x}{6 x}

(7 x - 2 x^{2} + 3) (x^{2} + 3)

f (x) = \frac{x - 1}{x ^{2} - 6 x + 8}

What is the domain of y=(arccos((2x)/(1+x))) ?
The domain of y=(arccos((2x)/(1+x))) is -1/3 <= x<= 1