What is the domain of f(x)= 1/(sqrt(t+8)) ?

The domain of f(x)= 1/(sqrt(t+8)) is t>-8

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domain of f(x)= 1/(sqrt(t+8))

domain

f (x) = \frac{1}{t + 8}

t > - 8

Interval Notation

(- 8, \infty)

Solution steps

Find non-negative values for radicals:

t \geq - 8

Find undefined (singularity) points:

t = - 8

Combine real regions and undefined points for final function domain

t > - 8

f (x) = \frac{x ^{3} + 3}{4 x}

ln (- 3 x)

f (x) = \frac{x + 1}{x - 5} + 1

f (x) = \frac{2 x ^{2}}{x ^{3} - 2 x ^{2} - 8 x}

f (x) = \frac{6 x}{x - 2}

What is the domain of f(x)= 1/(sqrt(t+8)) ?
The domain of f(x)= 1/(sqrt(t+8)) is t>-8