What is the domain of f(x)=(x^2-2x-3)/(3x-7) ?

The domain of f(x)=(x^2-2x-3)/(3x-7) is x 7/3

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domain of f(x)=(x^2-2x-3)/(3x-7)

domain

f (x) = \frac{x ^{2} - 2 x - 3}{3 x - 7}

x < \frac{7}{3} or x > \frac{7}{3}

Interval Notation

(- \infty, \frac{7}{3}) \cup (\frac{7}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{7}{3}

The function domain

x < \frac{7}{3} or x > \frac{7}{3}

f (x) = \frac{3}{lo g _{10} ( 2 x - 1 ) + 1}

f (x) = \frac{x - 5}{( x - 7 ) ( x + 3 )}

f (x) = 2 x - 1 + x

f (x) = \frac{x ^{2} - x - 2}{x ^{4} - 81}

f (x) = - 84 x - 2

What is the domain of f(x)=(x^2-2x-3)/(3x-7) ?
The domain of f(x)=(x^2-2x-3)/(3x-7) is x< 7/3 \lor x> 7/3