What is the domain of sqrt(sin(3x-pi/4)) ?

The domain of sqrt(sin(3x-pi/4)) is pi/(12)+(2pi)/3 n<= x<= (5pi}{12}+\frac{2pi)/3 n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(sin(3x-pi/4))

domain

sin (3 x - \frac{π}{4})

\frac{π}{12} + \frac{2 π}{3} n \leq x \leq \frac{5 π}{12} + \frac{2 π}{3} n

Interval Notation

[\frac{π}{12} + \frac{2 π}{3} n, \frac{5 π}{12} + \frac{2 π}{3} n]

Solution steps

Find non-negative values for radicals:

\frac{π}{12} + \frac{2 π}{3} n \leq x \leq \frac{5 π}{12} + \frac{2 π}{3} n

The function domain

\frac{π}{12} + \frac{2 π}{3} n \leq x \leq \frac{5 π}{12} + \frac{2 π}{3} n

f (x) = f (x) = 7 + ln (3 x + 1)

y = \frac{- 3 x - 8}{- 8 x - 20}

f (x) = lo g_{2} (3 x^{2} - 5 x + 2)

f (x) = e^{3 x} - x - 9

x + 4 (\frac{x + 1}{2})

What is the domain of sqrt(sin(3x-pi/4)) ?
The domain of sqrt(sin(3x-pi/4)) is pi/(12)+(2pi)/3 n<= x<= (5pi}{12}+\frac{2pi)/3 n