What is the domain of g(y)= 4/(y^2-y) ?

The domain of g(y)= 4/(y^2-y) is y 1

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domain of g(y)= 4/(y^2-y)

domain

g (y) = \frac{4}{y ^{2} - y}

y < 0 or 0 < y < 1 or y > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

y = 1, y = 0

The function domain

y < 0 or 0 < y < 1 or y > 1

f (x) = - 2 x - 3

y = \frac{5 x}{x ^{2} + 81}

f (x) = \frac{2 - x}{x ^{2} - 9}

f (x) = \frac{2 x ^{2} - 2 x}{x ^{4}}

f (x) = - 13 x + 1

What is the domain of g(y)= 4/(y^2-y) ?
The domain of g(y)= 4/(y^2-y) is y<0\lor 0<y<1\lor y>1