What is the critical f(x)=2x^3-3x^2-12x+1 ?

The critical f(x)=2x^3-3x^2-12x+1 is x=-1,x=2

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critical f(x)=2x^3-3x^2-12x+1

critical points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 1

x = - 1, x = 2

Solution steps

2 x^{3} - 3 x^{2} - 12 x + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 2

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} - 3 x^{2} - 12 x + 1 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 2

f (x) = \frac{( x - 5 )}{3}

y = \frac{1}{x - 8}

f (x) = \frac{1}{x ^{2} - 2}

- x^{3} + 3 x^{2} + 10 x

lo g_{3} (x - 2)

What is the critical f(x)=2x^3-3x^2-12x+1 ?
The critical f(x)=2x^3-3x^2-12x+1 is x=-1,x=2