What is the domain of f(x)=sqrt(1-(x^2)/(16)) ?

The domain of f(x)=sqrt(1-(x^2)/(16)) is -4<= x<= 4

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domain of f(x)=sqrt(1-(x^2)/(16))

domain

f (x) = 1 - \frac{x ^{2}}{16}

- 4 \leq x \leq 4

Interval Notation

[- 4, 4]

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq 4

The function domain

- 4 \leq x \leq 4

f (x) = \frac{1 - 3 x}{x ^{3} - 4 x ^{2} - 5 x}

\frac{\frac{2}{x}}{\frac{4}{x + 4}}

f (x) = (x - 1)^{(2)} + 3

3 w (2 - 3 u) = 6 u - 3

∣ - 19 + 6 x ∣

What is the domain of f(x)=sqrt(1-(x^2)/(16)) ?
The domain of f(x)=sqrt(1-(x^2)/(16)) is -4<= x<= 4