What is the domain of f(x)=2sqrt(x^2-5x+6) ?

The domain of f(x)=2sqrt(x^2-5x+6) is x = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=2sqrt(x^2-5x+6)

domain

f (x) = 2 x^{2} - 5 x + 6

x \leq 2 or x \geq 3

Interval Notation

(- \infty, 2] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 3

The function domain

x \leq 2 or x \geq 3

f (x) = e^{x} - 8

f (x) = - \frac{15}{8}

f (x) = \frac{5 x + 5}{7 x + 21}

\frac{ln ( x ^{2} + 8 x + 15 )}{2 - x}

f (x) = \frac{2 x + 1}{x - 2}

What is the domain of f(x)=2sqrt(x^2-5x+6) ?
The domain of f(x)=2sqrt(x^2-5x+6) is x<= 2\lor x>= 3