What is the domain of f(x)=10sqrt(-9x+6) ?

The domain of f(x)=10sqrt(-9x+6) is x<= 2/3

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domain of f(x)=10sqrt(-9x+6)

domain

f (x) = 10 - 9 x + 6

x \leq \frac{2}{3}

Interval Notation

(- \infty, \frac{2}{3}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{2}{3}

The function domain

x \leq \frac{2}{3}

f (x) = 0.5 (35 - 2 x)

2 x^{3} - 17 x^{2} - 31 x + 20

x^{3} - x^{2} - 6 x

\frac{- 7 - 4 x}{x - 9}

f (x) = 2 x + 3

What is the domain of f(x)=10sqrt(-9x+6) ?
The domain of f(x)=10sqrt(-9x+6) is x<= 2/3