What is the domain of f(x)=(2x^2+1)/(1/16 x^2+3) ?

The domain of f(x)=(2x^2+1)/(1/16 x^2+3) is -infinity <x<infinity

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domain of f(x)=(2x^2+1)/(1/16 x^2+3)

domain

f (x) = \frac{2 x ^{2} + 1}{\frac{1}{16} x ^{2} + 3}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = \frac{3 x}{x + 1}

f (x) = \frac{x - 1}{2 ( x + 1 )}

f (x) = \frac{4 x + 8}{x ^{2} + 4 x - 32}

\frac{2}{9 x}

\frac{x - 4}{5 x - 3}

What is the domain of f(x)=(2x^2+1)/(1/16 x^2+3) ?
The domain of f(x)=(2x^2+1)/(1/16 x^2+3) is -infinity <x<infinity