What is the domain of y=(sqrt(x-1))/(sqrt(x^2-x-2)) ?

The domain of y=(sqrt(x-1))/(sqrt(x^2-x-2)) is x>2

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domain of y=(sqrt(x-1))/(sqrt(x^2-x-2))

domain

y = \frac{x - 1}{x ^{2} - x - 2}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2, x = - 1

Combine real regions and undefined points for final function domain

x > 2

x - 2 sin (x)

\frac{\frac{7 y ^{4}}{8}}{\frac{5 y ^{6}}{3}}

g (x) = 5 x + 10

- \frac{4 x ^{2} + 12 x - 39}{8}

x \cdot \frac{( 3 x ^{2} )}{x \cdot 5 ^{- \frac{1}{x}} + 2}

What is the domain of y=(sqrt(x-1))/(sqrt(x^2-x-2)) ?
The domain of y=(sqrt(x-1))/(sqrt(x^2-x-2)) is x>2