What is the domain of y=sqrt(x-2),x>= 2 ?

The domain of y=sqrt(x-2),x>= 2 is x>= 2

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domain of y=sqrt(x-2),x>= 2

domain

y = x - 2, x \geq 2

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Set the domain to the given interval

x \geq 2

Find non-negative values for radicals:

x \geq 2

Join real regions with the domain:

x \geq 2 and x \geq 2

x \geq 2

arccos (\frac{2 arcsin ( \frac{1}{4 x ^{2} - 1} )}{π})

f (x) = 84 x^{2} - x^{3}

\frac{\frac{8}{x + 6}}{\frac{7}{x}}

f (x) = \frac{x}{4 x - 9}

y = \frac{x ^{3} + 2}{x + 1}

What is the domain of y=sqrt(x-2),x>= 2 ?
The domain of y=sqrt(x-2),x>= 2 is x>= 2