What is the domain of f(x)=log_{3}(x+1)-2 ?

The domain of f(x)=log_{3}(x+1)-2 is x>-1

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domain of f(x)=log_{3}(x+1)-2

domain

f (x) = lo g_{3} (x + 1) - 2

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find positive values for logs:

x > - 1

The function domain

x > - 1

f (x) = \frac{7 x}{x + 6}

lo g_{10} (1)

f (x) = 3 + lo g_{2} (x - 2)

arcsin (2^{2 x} - 3 \cdot 2^{x} + 1)

\frac{x + 5}{( x - 1 ) ( x + 2 )}

What is the domain of f(x)=log_{3}(x+1)-2 ?
The domain of f(x)=log_{3}(x+1)-2 is x>-1