What is the domain of (sin(x))/(7-e^{2x-3)} ?

The domain of (sin(x))/(7-e^{2x-3)} is x (ln(7)+3)/2

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domain of (sin(x))/(7-e^{2x-3)}

domain

\frac{sin ( x )}{7 - e ^{2 x - 3}}

x < \frac{ln ( 7 ) + 3}{2} or x > \frac{ln ( 7 ) + 3}{2}

Interval Notation

(- \infty, \frac{ln ( 7 ) + 3}{2}) \cup (\frac{ln ( 7 ) + 3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{ln ( 7 ) + 3}{2}

The function domain

x < \frac{ln ( 7 ) + 3}{2} or x > \frac{ln ( 7 ) + 3}{2}

f (x) = \frac{x - 2}{x ^{2} + x - 2}

y = x^{2} + 36

f (t) = 55 + 35

v (x) = \frac{x}{x ^{2} + 64}

f (x) = \frac{5}{x ^{2} - 4 - 2}

What is the domain of (sin(x))/(7-e^{2x-3)} ?
The domain of (sin(x))/(7-e^{2x-3)} is x<(ln(7)+3)/2 \lor x>(ln(7)+3)/2