What is the domain of f(x)=\sqrt[5]{x^2-1} ?

The domain of f(x)=\sqrt[5]{x^2-1} is -infinity <x<infinity

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domain of f(x)=\sqrt[5]{x^2-1}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - \frac{6}{( x + 1 ) ^{2}}

f (x) = x^{4} - 8 x^{2}

ln (x) - 2

f (x) = 2 csc (2 x)

f (x) = - 2 0^{2} + 360 x + 1000

What is the domain of f(x)=\sqrt[5]{x^2-1} ?
The domain of f(x)=\sqrt[5]{x^2-1} is -infinity <x<infinity