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Popular >

range of x^2-8x+15

Solution

range

x^{2} - 8 x + 15

Solution

f (x) \geq - 1

+1

Interval Notation

[- 1, \infty)

Solution steps

Vertex of

x^{2} - 8 x + 15 :

Minimum

(4, - 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (4, - 1)

f (x) \geq - 1

Popular Examples

parallel y-4x=-1 parallel

y - 4 x = - 1

asymptotes of f(x)= 4/(x-1)-2 asymptotes

f (x) = \frac{4}{x - 1} - 2

inverse of f(127)=x^3+2 inverse

f (127) = x^{3} + 2

range of f(x)=arcsin(x)range

f (x) = arcsin (x)

intercepts of f(x)=-1/3 (x-1)^2+1 intercepts

f (x) = - \frac{1}{3} (x - 1)^{2} + 1

Frequently Asked Questions (FAQ)

What is the range of x^2-8x+15 ?
The range of x^2-8x+15 is f(x)>=-1