What is the domain of f(x)=(sqrt(8+x))/(7-x) ?

The domain of f(x)=(sqrt(8+x))/(7-x) is -8 7

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domain of f(x)=(sqrt(8+x))/(7-x)

domain

f (x) = \frac{8 + x}{7 - x}

- 8 \leq x < 7 or x > 7

Interval Notation

[- 8, 7) \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = 7

Combine real regions and undefined points for final function domain

- 8 \leq x < 7 or x > 7

4 (x) + 1

y = 10 - x

(x + 1) 2

f (x) = - (2 x - 1)

f (x) = - \frac{x ^{2} - 8}{3}

What is the domain of f(x)=(sqrt(8+x))/(7-x) ?
The domain of f(x)=(sqrt(8+x))/(7-x) is -8<= x<7\lor x>7