What is the domain of 1/(1+\frac{1){1+1/x}} ?

The domain of 1/(1+\frac{1){1+1/x}} is x 0

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domain of 1/(1+\frac{1){1+1/x}}

domain

\frac{1}{1 + \frac{1}{1 + \frac{1}{x}}}

x < - 1 or - 1 < x < - \frac{1}{2} or - \frac{1}{2} < x < 0 or x > 0

Interval Notation

(- \infty, - 1) \cup (- 1, - \frac{1}{2}) \cup (- \frac{1}{2}, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{2}, x = - 1, x = 0

The function domain

x < - 1 or - 1 < x < - \frac{1}{2} or - \frac{1}{2} < x < 0 or x > 0

\frac{x ^{2} - 16}{x ^{3} + 5 x ^{2} + 6 x}

f (x) = ln (9 - 4 x)

f (x) = (x + 2)^{2} + (y - 5)^{2} = 16

f (x) = \frac{x - 3}{x ^{3} - 27}

arcsin (\frac{x}{x - 1})

What is the domain of 1/(1+\frac{1){1+1/x}} ?
The domain of 1/(1+\frac{1){1+1/x}} is x<-1\lor-1<x<-1/2 \lor-1/2 <x<0\lor x>0