What is the domain of u(x)=sqrt(-8x+16) ?

The domain of u(x)=sqrt(-8x+16) is x<= 2

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domain of u(x)=sqrt(-8x+16)

domain

u (x) = - 8 x + 16

x \leq 2

Interval Notation

(- \infty, 2]

Solution steps

Find non-negative values for radicals:

x \leq 2

The function domain

x \leq 2

f (x) = - \frac{1}{2 ( x + 1 )} + 3

f (x) = e^{a r c t a n (x)}

y, y \leq - x

f (x) = \frac{- 7 - 4 x}{7 ( - 1 - x )}

f (x) = \frac{2}{x} + \frac{1}{x ^{2} - 1}

What is the domain of u(x)=sqrt(-8x+16) ?
The domain of u(x)=sqrt(-8x+16) is x<= 2