What is the domain of (sqrt(5x-2))+(4x+1) ?

The domain of (sqrt(5x-2))+(4x+1) is x>= 2/5

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domain of (sqrt(5x-2))+(4x+1)

domain

(5 x - 2) + (4 x + 1)

x \geq \frac{2}{5}

Interval Notation

[\frac{2}{5}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{2}{5}

The function domain

x \geq \frac{2}{5}

f (x) = - 4 x - 1

f (x) = ln (\frac{x ^{4}}{x + 2})

f (x) = - 4 x - 2

- \frac{1}{4 - x ^{2}}

\frac{2 x - 3}{x + 5}

What is the domain of (sqrt(5x-2))+(4x+1) ?
The domain of (sqrt(5x-2))+(4x+1) is x>= 2/5