What is the domain of g(x)=((x^2-1))/((x+1)) ?

The domain of g(x)=((x^2-1))/((x+1)) is x -1

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domain of g(x)=((x^2-1))/((x+1))

domain

g (x) = \frac{( x ^{2} - 1 )}{( x + 1 )}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

y = x^{2} + 4 x

f (x) = \frac{2 x + 1}{x - 4}

f (x) = ln (- 3 x + 6)

g (x) = 2 x^{2} - 4

\frac{5 - 3 x}{2}

What is the domain of g(x)=((x^2-1))/((x+1)) ?
The domain of g(x)=((x^2-1))/((x+1)) is x<-1\lor x>-1