What is the domain of y=(2x^2-5x+3)/(4x-5) ?

The domain of y=(2x^2-5x+3)/(4x-5) is x 5/4

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domain of y=(2x^2-5x+3)/(4x-5)

domain

y = \frac{2 x ^{2} - 5 x + 3}{4 x - 5}

x < \frac{5}{4} or x > \frac{5}{4}

Interval Notation

(- \infty, \frac{5}{4}) \cup (\frac{5}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{5}{4}

The function domain

x < \frac{5}{4} or x > \frac{5}{4}

\frac{( 4 x - 5 )}{2 ( x ^{2} - 1 )}

y = \frac{2 x ^{2} - 5 x + 3}{4 x - 6}

f (x) = ∣ x ∣ + x

lo g_{x} (\frac{x}{x - 2}) - 2

f (x) = 12 x^{2} + 98 x + 196

What is the domain of y=(2x^2-5x+3)/(4x-5) ?
The domain of y=(2x^2-5x+3)/(4x-5) is x< 5/4 \lor x> 5/4